Hi,
I am modeling positron annihilation using Na22 as my primary particle. I am trying to enable sampling of entanglement but it is showing ‘OFF’. Is there a way to do it in the PhysicsList.cc. I am using the following main physics lists
This gives the positronium a small thermal motion, so the gammas in 2-gamma annihilation are not quite back-to-back. See comments in source/processes//electromagnetic/standard/src/G4eeToTwoGammaModel.cc:
// In rest frame of positronium gammas are back to back
const G4ThreeVector& dir1 = G4RandomDirection();
const G4ThreeVector& dir2 = -dir1;
aGamma1 = new G4DynamicParticle(G4Gamma::Gamma(),dir1,eGamma);
aGamma2 = new G4DynamicParticle(G4Gamma::Gamma(),dir2,eGamma);
// In rest frame the gammas are polarised perpendicular to each other - see
// Pryce and Ward, Nature No 4065 (1947) p.435.
// Snyder et al, Physical Review 73 (1948) p.440.
G4ThreeVector pol1 = (G4RandomDirection().cross(dir1)).unit();
G4ThreeVector pol2 = (pol1.cross(dir2)).unit();
// But the positronium is moving...
// A positron in matter slows down and combines with an atomic electron to
// make a neutral atom called positronium, about half the size of a normal
// atom. I expect that when the energy of the positron is small enough,
// less than the binding energy of positronium (6.8 eV), it is
// energetically favourable for an electron from the outer orbitals of a
// nearby atom or molecule to transfer and bind to the positron, as in an
// ionic bond, leaving behind a mildly ionised nearby atom/molecule. I
// would expect the positronium to come away with a kinetic energy of a
// few eV on average. In its para (spin 0) state it annihilates into two
// photons, which in the rest frame of the positronium are collinear
// (back-to-back) due to momentum conservation. Because of the motion of the
// positronium, photons will be not quite back-to-back in the laboratory.
// The positroniuim acquires an energy of order its binding energy and
// doesn't have time to thermalise. Nevertheless, here we approximate its
// energy distribution by a Maxwell-Boltzman with mean energy <KE>. In terms
// of a more familiar concept of temperature, and the law of equipartition
// of energy of translational motion, <KE>=3kT/2. Each component of velocity
// has a distribution exp(-mv^2/2kT), which is a Gaussian of mean zero
// and variance kT/m=2<KE>/3m, where m is the positronium mass.
// We take <KE> = material->GetIonisation()->GetMeanEnergyPerIonPair().
